Base | Representation |
---|---|
bin | 10011100001001000010… |
… | …000101011111100101111 |
3 | 11202012222110200202001201 |
4 | 103201020100223330233 |
5 | 133433330441131343 |
6 | 2504054053350331 |
7 | 165621142000162 |
oct | 23411020537457 |
9 | 4665873622051 |
10 | 1341242130223 |
11 | 4778aa242036 |
12 | 197b373383a7 |
13 | 9962b6024a8 |
14 | 48cb8ad1ad9 |
15 | 24d4e9ba94d |
hex | 1384842bf2f |
1341242130223 has 2 divisors, whose sum is σ = 1341242130224. Its totient is φ = 1341242130222.
The previous prime is 1341242130187. The next prime is 1341242130257. The reversal of 1341242130223 is 3220312421431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1341242130223 - 233 = 1332652195631 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1341242130191 and 1341242130200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341242130923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670621065111 + 670621065112.
It is an arithmetic number, because the mean of its divisors is an integer number (670621065112).
Almost surely, 21341242130223 is an apocalyptic number.
1341242130223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341242130223 is an equidigital number, since it uses as much as digits as its factorization.
1341242130223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1341242130223 its reverse (3220312421431), we get a palindrome (4561554551654).
The spelling of 1341242130223 in words is "one trillion, three hundred forty-one billion, two hundred forty-two million, one hundred thirty thousand, two hundred twenty-three".
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