13412423404053 has 24 divisors (see below), whose sum is σ = 19381116867840. Its totient is φ = 8938100891520.

The previous prime is 13412423404021. The next prime is 13412423404057. The reversal of 13412423404053 is 35040432421431.

13412423404053 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 242 + 3 + 4 + 0 + 405 + 3 = 666.

It is not a de Polignac number, because 13412423404053 - 2⁵ = 13412423404021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13412423403999 and 13412423404017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13412423404057) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 578035350 + ... + 578058552.

It is an arithmetic number, because the mean of its divisors is an integer number (807546536160).

Almost surely, 2^{13412423404053} is an apocalyptic number.

It is an amenable number.

13412423404053 is a deficient number, since it is larger than the sum of its proper divisors (5968693463787).

13412423404053 is a wasteful number, since it uses less digits than its factorization.

13412423404053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45689 (or 45686 counting only the distinct ones).

The product of its (nonzero) digits is 138240, while the sum is 36.

Adding to 13412423404053 its reverse (35040432421431), we get a palindrome (48452855825484).

The spelling of 13412423404053 in words is "thirteen trillion, four hundred twelve billion, four hundred twenty-three million, four hundred four thousand, fifty-three".