Base | Representation |
---|---|
bin | 1100001100101101001111… |
… | …1010110010100110011101 |
3 | 1202111012212020100011001111 |
4 | 3003023103322302212131 |
5 | 3224222140441133201 |
6 | 44305331423542021 |
7 | 2553005564001601 |
oct | 303132372624635 |
9 | 52435766304044 |
10 | 13412443302301 |
11 | 43012046452aa |
12 | 160750815a911 |
13 | 763a32251514 |
14 | 345246a3d501 |
15 | 183d4d6b9b51 |
hex | c32d3eb299d |
13412443302301 has 2 divisors, whose sum is σ = 13412443302302. Its totient is φ = 13412443302300.
The previous prime is 13412443302259. The next prime is 13412443302337. The reversal of 13412443302301 is 10320334421431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11510236870276 + 1902206432025 = 3392674^2 + 1379205^2 .
It is a cyclic number.
It is not a de Polignac number, because 13412443302301 - 219 = 13412442778013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13412443302901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706221651150 + 6706221651151.
It is an arithmetic number, because the mean of its divisors is an integer number (6706221651151).
Almost surely, 213412443302301 is an apocalyptic number.
It is an amenable number.
13412443302301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412443302301 is an equidigital number, since it uses as much as digits as its factorization.
13412443302301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13412443302301 its reverse (10320334421431), we get a palindrome (23732777723732).
The spelling of 13412443302301 in words is "thirteen trillion, four hundred twelve billion, four hundred forty-three million, three hundred two thousand, three hundred one".
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