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13412599139 is a prime number
BaseRepresentation
bin11000111110111010…
…00000010101100011
31021121202011122002002
430133131000111203
5204432111133024
610054530314215
7653243132402
oct143735002543
937552148062
1013412599139
115763076285
122723a2896b
131359a04bc4
1491348d639
155377a36ae
hex31f740563

13412599139 has 2 divisors, whose sum is σ = 13412599140. Its totient is φ = 13412599138.

The previous prime is 13412599091. The next prime is 13412599217. The reversal of 13412599139 is 93199521431.

13412599139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13412599139 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13412599093 and 13412599102.

It is not a weakly prime, because it can be changed into another prime (13412599639) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706299569 + 6706299570.

It is an arithmetic number, because the mean of its divisors is an integer number (6706299570).

Almost surely, 213412599139 is an apocalyptic number.

13412599139 is a deficient number, since it is larger than the sum of its proper divisors (1).

13412599139 is an equidigital number, since it uses as much as digits as its factorization.

13412599139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 262440, while the sum is 47.

The spelling of 13412599139 in words is "thirteen billion, four hundred twelve million, five hundred ninety-nine thousand, one hundred thirty-nine".