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1341300330113 is a prime number
BaseRepresentation
bin10011100001001011101…
…110101100111010000001
311202020010112012121022012
4103201023232230322001
5133433440341030423
62504103533022305
7165622446456152
oct23411356547201
94666115177265
101341300330113
1147792a083517
12197b52924995
139963a69bcb3
1448cc2721929
1524d54b65078
hex1384bbace81

1341300330113 has 2 divisors, whose sum is σ = 1341300330114. Its totient is φ = 1341300330112.

The previous prime is 1341300330107. The next prime is 1341300330121. The reversal of 1341300330113 is 3110330031431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1295242019569 + 46058310544 = 1138087^2 + 214612^2 .

It is a cyclic number.

It is not a de Polignac number, because 1341300330113 - 218 = 1341300067969 is a prime.

It is a super-2 number, since 2×13413003301132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1341300330173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670650165056 + 670650165057.

It is an arithmetic number, because the mean of its divisors is an integer number (670650165057).

Almost surely, 21341300330113 is an apocalyptic number.

It is an amenable number.

1341300330113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341300330113 is an equidigital number, since it uses as much as digits as its factorization.

1341300330113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1341300330113 its reverse (3110330031431), we get a palindrome (4451630361544).

The spelling of 1341300330113 in words is "one trillion, three hundred forty-one billion, three hundred million, three hundred thirty thousand, one hundred thirteen".