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1341300403 = 6722987421
BaseRepresentation
bin100111111110010…
…1001111010110011
310110110220010020201
41033330221322303
510221333103103
6341032420031
745144602542
oct11774517263
93413803221
101341300403
11629146933
12315247617
13184b686a1
14ca1d2159
157cb4c51d
hex4ff29eb3

1341300403 has 8 divisors (see below), whose sum is σ = 1367280080. Its totient is φ = 1315496160.

The previous prime is 1341300379. The next prime is 1341300437. The reversal of 1341300403 is 3040031431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1341300403 - 25 = 1341300371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341306403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28368 + ... + 59053.

It is an arithmetic number, because the mean of its divisors is an integer number (170910010).

Almost surely, 21341300403 is an apocalyptic number.

1341300403 is a deficient number, since it is larger than the sum of its proper divisors (25979677).

1341300403 is an equidigital number, since it uses as much as digits as its factorization.

1341300403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87717.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 1341300403 is about 36623.7682796296. The cubic root of 1341300403 is about 1102.8302880379.

Adding to 1341300403 its reverse (3040031431), we get a palindrome (4381331834).

It can be divided in two parts, 13 and 41300403, that added together give a triangular number (41300416 = T9088).

The spelling of 1341300403 in words is "one billion, three hundred forty-one million, three hundred thousand, four hundred three".

Divisors: 1 67 229 15343 87421 5857207 20019409 1341300403