Base | Representation |
---|---|
bin | 11000111110111110… |
… | …10011110001100010 |
3 | 1021121210022022110212 |
4 | 30133133103301202 |
5 | 204432234444132 |
6 | 10054551254122 |
7 | 653251226141 |
oct | 143737236142 |
9 | 37553268425 |
10 | 13413203042 |
11 | 5763448a78 |
12 | 272407a342 |
13 | 1359b86a45 |
14 | 9135a9758 |
15 | 5378725b2 |
hex | 31f7d3c62 |
13413203042 has 4 divisors (see below), whose sum is σ = 20119804566. Its totient is φ = 6706601520.
The previous prime is 13413203033. The next prime is 13413203051. The reversal of 13413203042 is 24030231431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24030231431 = 3463 ⋅6939137.
It is an interprime number because it is at equal distance from previous prime (13413203033) and next prime (13413203051).
It can be written as a sum of positive squares in only one way, i.e., 9335231161 + 4077971881 = 96619^2 + 63859^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13413202999 and 13413203017.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3353300759 + ... + 3353300762.
Almost surely, 213413203042 is an apocalyptic number.
13413203042 is a deficient number, since it is larger than the sum of its proper divisors (6706601524).
13413203042 is an equidigital number, since it uses as much as digits as its factorization.
13413203042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6706601523.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13413203042 its reverse (24030231431), we get a palindrome (37443434473).
The spelling of 13413203042 in words is "thirteen billion, four hundred thirteen million, two hundred three thousand, forty-two".
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