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1341324331041 = 33244031378249
BaseRepresentation
bin10011100001001101001…
…010010000100000100001
311202020012012100222101110
4103201031022100200201
5133434013012043131
62504110151253533
7165623160460542
oct23411512204041
94666165328343
101341324331041
114779416867a2
12197b5a97a2a9
1399642653526
1448cc59ac4c9
1524d56d06646
hex1384d290821

1341324331041 has 8 divisors (see below), whose sum is σ = 1788439252000. Its totient is φ = 894212815392.

The previous prime is 1341324331033. The next prime is 1341324331093. The reversal of 1341324331041 is 1401334231431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1341324331041 - 23 = 1341324331033 is a prime.

It is a super-2 number, since 2×13413243310412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341324331541) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 284085 + ... + 1662333.

It is an arithmetic number, because the mean of its divisors is an integer number (223554906500).

Almost surely, 21341324331041 is an apocalyptic number.

It is an amenable number.

1341324331041 is a deficient number, since it is larger than the sum of its proper divisors (447114920959).

1341324331041 is a wasteful number, since it uses less digits than its factorization.

1341324331041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1702655.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 1341324331041 its reverse (1401334231431), we get a palindrome (2742658562472).

The spelling of 1341324331041 in words is "one trillion, three hundred forty-one billion, three hundred twenty-four million, three hundred thirty-one thousand, forty-one".

Divisors: 1 3 324403 973209 1378249 4134747 447108110347 1341324331041