Base | Representation |
---|---|
bin | 10011100001001101101… |
… | …001001111101101010011 |
3 | 11202020012202122200022012 |
4 | 103201031221033231103 |
5 | 133434022102013402 |
6 | 2504111041333135 |
7 | 165623316512363 |
oct | 23411551175523 |
9 | 4666182580265 |
10 | 1341332454227 |
11 | 477946224877 |
12 | 197b616371ab |
13 | 99644238a4c |
14 | 48cc6ac49a3 |
15 | 24d578ad452 |
hex | 1384da4fb53 |
1341332454227 has 2 divisors, whose sum is σ = 1341332454228. Its totient is φ = 1341332454226.
The previous prime is 1341332454199. The next prime is 1341332454229. The reversal of 1341332454227 is 7224542331431.
It is a strong prime.
It is an emirp because it is prime and its reverse (7224542331431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1341332454227 - 216 = 1341332388691 is a prime.
Together with 1341332454229, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1341332454229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670666227113 + 670666227114.
It is an arithmetic number, because the mean of its divisors is an integer number (670666227114).
Almost surely, 21341332454227 is an apocalyptic number.
1341332454227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341332454227 is an equidigital number, since it uses as much as digits as its factorization.
1341332454227 is an evil number, because the sum of its binary digits is even.
The product of its digits is 483840, while the sum is 41.
Adding to 1341332454227 its reverse (7224542331431), we get a palindrome (8565874785658).
The spelling of 1341332454227 in words is "one trillion, three hundred forty-one billion, three hundred thirty-two million, four hundred fifty-four thousand, two hundred twenty-seven".
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