Base | Representation |
---|---|
bin | 11110011111111001011010… |
… | …010110001100110001100111 |
3 | 122120221000121101202112012212 |
4 | 132133321122112030301213 |
5 | 120040120042133014030 |
6 | 1153140001401434035 |
7 | 40152546213463430 |
oct | 3637713226146147 |
9 | 576830541675185 |
10 | 134133344423015 |
11 | 398146a5094493 |
12 | 13063b3579b91b |
13 | 59ac9490bc572 |
14 | 251a134c28487 |
15 | 10791b1ce2595 |
hex | 79fe5a58cc67 |
134133344423015 has 16 divisors (see below), whose sum is σ = 183954832386048. Its totient is φ = 91976884730016.
The previous prime is 134133344423009. The next prime is 134133344423041. The reversal of 134133344423015 is 510324443331431.
It is a cyclic number.
It is not a de Polignac number, because 134133344423015 - 24 = 134133344422999 is a prime.
It is a super-2 number, since 2×1341333444230152 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7161674 + ... + 17876136.
It is an arithmetic number, because the mean of its divisors is an integer number (11497177024128).
Almost surely, 2134133344423015 is an apocalyptic number.
134133344423015 is a deficient number, since it is larger than the sum of its proper divisors (49821487963033).
134133344423015 is a wasteful number, since it uses less digits than its factorization.
134133344423015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11072158.
The product of its (nonzero) digits is 622080, while the sum is 41.
Adding to 134133344423015 its reverse (510324443331431), we get a palindrome (644457787754446).
The spelling of 134133344423015 in words is "one hundred thirty-four trillion, one hundred thirty-three billion, three hundred forty-four million, four hundred twenty-three thousand, fifteen".
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