1341344204133 has 4 divisors (see below), whose sum is σ = 1788458938848. Its totient is φ = 894229469420.

The previous prime is 1341344204111. The next prime is 1341344204141. The reversal of 1341344204133 is 3314024431431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341344204133 - 2¹² = 1341344200037 is a prime.

It is a super-2 number, since 2×1341344204133² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1341344204094 and 1341344204103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341344204153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223557367353 + ... + 223557367358.

It is an arithmetic number, because the mean of its divisors is an integer number (447114734712).

Almost surely, 2^{1341344204133} is an apocalyptic number.

It is an amenable number.

1341344204133 is a deficient number, since it is larger than the sum of its proper divisors (447114734715).

1341344204133 is an equidigital number, since it uses as much as digits as its factorization.

1341344204133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 447114734714.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1341344204133 its reverse (3314024431431), we get a palindrome (4655368635564).

The spelling of 1341344204133 in words is "one trillion, three hundred forty-one billion, three hundred forty-four million, two hundred four thousand, one hundred thirty-three".