Base | Representation |
---|---|
bin | 10011100001001111011… |
… | …110011101000000100101 |
3 | 11202020021220110200112101 |
4 | 103201033132131000211 |
5 | 133434102433221212 |
6 | 2504114100052101 |
7 | 165624141621532 |
oct | 23411736350045 |
9 | 4666256420471 |
10 | 1341363179557 |
11 | 477961600205 |
12 | 197b6b994031 |
13 | 9964a705c0b |
14 | 48ccac01d89 |
15 | 24d5a42c157 |
hex | 1384f79d025 |
1341363179557 has 2 divisors, whose sum is σ = 1341363179558. Its totient is φ = 1341363179556.
The previous prime is 1341363179447. The next prime is 1341363179641. The reversal of 1341363179557 is 7559713631431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1330160862276 + 11202317281 = 1153326^2 + 105841^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1341363179557 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1341363179498 and 1341363179507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341363179657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670681589778 + 670681589779.
It is an arithmetic number, because the mean of its divisors is an integer number (670681589779).
Almost surely, 21341363179557 is an apocalyptic number.
It is an amenable number.
1341363179557 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341363179557 is an equidigital number, since it uses as much as digits as its factorization.
1341363179557 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7144200, while the sum is 55.
The spelling of 1341363179557 in words is "one trillion, three hundred forty-one billion, three hundred sixty-three million, one hundred seventy-nine thousand, five hundred fifty-seven".
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