Base | Representation |
---|---|
bin | 10011100001010001110… |
… | …000000000000100011011 |
3 | 11202020101120021010122111 |
4 | 103201101300000010123 |
5 | 133434142220142133 |
6 | 2504121541533151 |
7 | 165625114132231 |
oct | 23412160000433 |
9 | 4666346233574 |
10 | 1341401334043 |
11 | 4779810a0241 |
12 | 197b807141b7 |
13 | 996555a4734 |
14 | 48cd1cd4951 |
15 | 24d5d9671cd |
hex | 13851c0011b |
1341401334043 has 2 divisors, whose sum is σ = 1341401334044. Its totient is φ = 1341401334042.
The previous prime is 1341401334001. The next prime is 1341401334067. The reversal of 1341401334043 is 3404331041431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1341401334043 - 217 = 1341401202971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1341401333996 and 1341401334014.
It is not a weakly prime, because it can be changed into another prime (1341401334073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670700667021 + 670700667022.
It is an arithmetic number, because the mean of its divisors is an integer number (670700667022).
Almost surely, 21341401334043 is an apocalyptic number.
1341401334043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341401334043 is an equidigital number, since it uses as much as digits as its factorization.
1341401334043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 1341401334043 its reverse (3404331041431), we get a palindrome (4745732375474).
The spelling of 1341401334043 in words is "one trillion, three hundred forty-one billion, four hundred one million, three hundred thirty-four thousand, forty-three".
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