13414042152141 has 4 divisors (see below), whose sum is σ = 17885389536192. Its totient is φ = 8942694768092.

The previous prime is 13414042152103. The next prime is 13414042152211. The reversal of 13414042152141 is 14125124041431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13414042152141 - 2¹³ = 13414042143949 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13414042152941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2235673692021 + ... + 2235673692026.

It is an arithmetic number, because the mean of its divisors is an integer number (4471347384048).

Almost surely, 2^{13414042152141} is an apocalyptic number.

It is an amenable number.

13414042152141 is a deficient number, since it is larger than the sum of its proper divisors (4471347384051).

13414042152141 is an equidigital number, since it uses as much as digits as its factorization.

13414042152141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4471347384050.

The product of its (nonzero) digits is 15360, while the sum is 33.

Adding to 13414042152141 its reverse (14125124041431), we get a palindrome (27539166193572).

The spelling of 13414042152141 in words is "thirteen trillion, four hundred fourteen billion, forty-two million, one hundred fifty-two thousand, one hundred forty-one".