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1341412222003 = 7191630317429
BaseRepresentation
bin10011100001010010011…
…001100010010000110011
311202020102022202022010021
4103201102121202100303
5133434203012101003
62504123011144311
7165625305520450
oct23412231422063
94666368668107
101341412222003
11477987257557
12197b842a5097
1399657917509
1448cd352a827
1524d5e8b82bd
hex13852662433

1341412222003 has 4 divisors (see below), whose sum is σ = 1533042539440. Its totient is φ = 1149781904568.

The previous prime is 1341412221991. The next prime is 1341412222039. The reversal of 1341412222003 is 3002222141431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1341412222003 - 221 = 1341410124851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341412222063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95815158708 + ... + 95815158721.

It is an arithmetic number, because the mean of its divisors is an integer number (383260634860).

Almost surely, 21341412222003 is an apocalyptic number.

1341412222003 is a deficient number, since it is larger than the sum of its proper divisors (191630317437).

1341412222003 is an equidigital number, since it uses as much as digits as its factorization.

1341412222003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191630317436.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1341412222003 its reverse (3002222141431), we get a palindrome (4343634363434).

The spelling of 1341412222003 in words is "one trillion, three hundred forty-one billion, four hundred twelve million, two hundred twenty-two thousand, three".

Divisors: 1 7 191630317429 1341412222003