1341413140234 has 8 divisors (see below), whose sum is σ = 2015109489060. Its totient is φ = 669709977216.

The previous prime is 1341413140213. The next prime is 1341413140241. The reversal of 1341413140234 is 4320413141431.

It can be written as a sum of positive squares in 2 ways, for example, as 1273519021009 + 67894119225 = 1128503^2 + 260565^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1341413140196 and 1341413140205.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 498294769 + ... + 498297460.

Almost surely, 2^{1341413140234} is an apocalyptic number.

1341413140234 is a deficient number, since it is larger than the sum of its proper divisors (673696348826).

1341413140234 is an equidigital number, since it uses as much as digits as its factorization.

1341413140234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 996592904.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1341413140234 its reverse (4320413141431), we get a palindrome (5661826281665).

The spelling of 1341413140234 in words is "one trillion, three hundred forty-one billion, four hundred thirteen million, one hundred forty thousand, two hundred thirty-four".