1341424331131 has 4 divisors (see below), whose sum is σ = 1343876661352. Its totient is φ = 1338972000912.

The previous prime is 1341424331123. The next prime is 1341424331147. The reversal of 1341424331131 is 1311334241431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1341424331131 - 2³ = 1341424331123 is a prime.

It is a super-2 number, since 2×1341424331131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1341424331093 and 1341424331102.

It is not an unprimeable number, because it can be changed into a prime (1341424338131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1226164290 + ... + 1226165383.

It is an arithmetic number, because the mean of its divisors is an integer number (335969165338).

Almost surely, 2^{1341424331131} is an apocalyptic number.

1341424331131 is a deficient number, since it is larger than the sum of its proper divisors (2452330221).

1341424331131 is an equidigital number, since it uses as much as digits as its factorization.

1341424331131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2452330220.

The product of its digits is 10368, while the sum is 31.

Adding to 1341424331131 its reverse (1311334241431), we get a palindrome (2652758572562).

The spelling of 1341424331131 in words is "one trillion, three hundred forty-one billion, four hundred twenty-four million, three hundred thirty-one thousand, one hundred thirty-one".