1341430431401 has 2 divisors, whose sum is σ = 1341430431402. Its totient is φ = 1341430431400.

The previous prime is 1341430431379. The next prime is 1341430431403. The reversal of 1341430431401 is 1041340341431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1155453006400 + 185977425001 = 1074920^2 + 431251^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1341430431401 is a prime.

Together with 1341430431403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1341430431403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670715215700 + 670715215701.

It is an arithmetic number, because the mean of its divisors is an integer number (670715215701).

Almost surely, 2^{1341430431401} is an apocalyptic number.

It is an amenable number.

1341430431401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341430431401 is an equidigital number, since it uses as much as digits as its factorization.

1341430431401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1341430431401 its reverse (1041340341431), we get a palindrome (2382770772832).

The spelling of 1341430431401 in words is "one trillion, three hundred forty-one billion, four hundred thirty million, four hundred thirty-one thousand, four hundred one".