Base | Representation |
---|---|
bin | 10011100001010011100… |
… | …001111110010100111001 |
3 | 11202020110122111001120100 |
4 | 103201103201332110321 |
5 | 133434222342230241 |
6 | 2504124530150013 |
7 | 165625626110055 |
oct | 23412341762471 |
9 | 4666418431510 |
10 | 1341431211321 |
11 | 477996a47503 |
12 | 197b8a722309 |
13 | 9965b8358b6 |
14 | 48cd5c70c65 |
15 | 24d613b99b6 |
hex | 1385387e539 |
1341431211321 has 54 divisors (see below), whose sum is σ = 2089502936430. Its totient is φ = 829112689152.
The previous prime is 1341431211301. The next prime is 1341431211331. The reversal of 1341431211321 is 1231121341431.
1341431211321 is a `hidden beast` number, since 1 + 3 + 4 + 14 + 312 + 11 + 321 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 581856212025 + 759574999296 = 762795^2 + 871536^2 .
It is not a de Polignac number, because 1341431211321 - 26 = 1341431211257 is a prime.
It is a super-2 number, since 2×13414312113212 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1341431211301) by changing a digit.
It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 11618445 + ... + 11733333.
Almost surely, 21341431211321 is an apocalyptic number.
It is an amenable number.
1341431211321 is a deficient number, since it is larger than the sum of its proper divisors (748071725109).
1341431211321 is a wasteful number, since it uses less digits than its factorization.
1341431211321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 115063 (or 114976 counting only the distinct ones).
The product of its digits is 1728, while the sum is 27.
Adding to 1341431211321 its reverse (1231121341431), we get a palindrome (2572552552752).
The spelling of 1341431211321 in words is "one trillion, three hundred forty-one billion, four hundred thirty-one million, two hundred eleven thousand, three hundred twenty-one".
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