Base | Representation |
---|---|
bin | 1100001100110100010100… |
… | …1010011000000101100010 |
3 | 1202111101202122100122010121 |
4 | 3003031011022120011202 |
5 | 3224240033330312120 |
6 | 44310244133350454 |
7 | 2553103633661206 |
oct | 303150512300542 |
9 | 52441678318117 |
10 | 13414343213410 |
11 | 4301a9a03a677 |
12 | 160795849842a |
13 | 763c75a53789 |
14 | 3453870c2b06 |
15 | 183e103ab5aa |
hex | c3345298162 |
13414343213410 has 16 divisors (see below), whose sum is σ = 24235579193400. Its totient is φ = 5345790305536.
The previous prime is 13414343213393. The next prime is 13414343213419. The reversal of 13414343213410 is 1431234341431.
It can be written as a sum of positive squares in 4 ways, for example, as 3831771015081 + 9582572198329 = 1957491^2 + 3095573^2 .
It is not an unprimeable number, because it can be changed into a prime (13414343213419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2493369655 + ... + 2493375034.
Almost surely, 213414343213410 is an apocalyptic number.
13414343213410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13414343213410 is a deficient number, since it is larger than the sum of its proper divisors (10821235979990).
13414343213410 is a wasteful number, since it uses less digits than its factorization.
13414343213410 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4986744965.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 13414343213410 its reverse (1431234341431), we get a palindrome (14845577554841).
The spelling of 13414343213410 in words is "thirteen trillion, four hundred fourteen billion, three hundred forty-three million, two hundred thirteen thousand, four hundred ten".
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