Base | Representation |
---|---|
bin | 10011100001010100001… |
… | …011101000100111011111 |
3 | 11202020111102000220112111 |
4 | 103201110023220213133 |
5 | 133434233141214242 |
6 | 2504130000214451 |
7 | 165626120664064 |
oct | 23412413504737 |
9 | 4666442026474 |
10 | 1341442132447 |
11 | 4779a212672a |
12 | 197b9230a427 |
13 | 99660b8a7c1 |
14 | 48cd74b4c6b |
15 | 24d62325817 |
hex | 138542e89df |
1341442132447 has 2 divisors, whose sum is σ = 1341442132448. Its totient is φ = 1341442132446.
The previous prime is 1341442132439. The next prime is 1341442132451. The reversal of 1341442132447 is 7442312441431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1341442132447 - 23 = 1341442132439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341442132477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670721066223 + 670721066224.
It is an arithmetic number, because the mean of its divisors is an integer number (670721066224).
Almost surely, 21341442132447 is an apocalyptic number.
1341442132447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341442132447 is an equidigital number, since it uses as much as digits as its factorization.
1341442132447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 258048, while the sum is 40.
Adding to 1341442132447 its reverse (7442312441431), we get a palindrome (8783754573878).
The spelling of 1341442132447 in words is "one trillion, three hundred forty-one billion, four hundred forty-two million, one hundred thirty-two thousand, four hundred forty-seven".
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