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13414440000 = 26354138599
BaseRepresentation
bin11000111111001000…
…00001110001000000
31021121212122011021010
430133210001301000
5204433044040000
610055034000520
7653264600343
oct143744016100
937555564233
1013414440000
115764113355
122724576140
13135a1caa80
1491380c45a
15537a18d50
hex31f901c40

13414440000 has 280 divisors, whose sum is σ = 47768459200. Its totient is φ = 3301632000.

The previous prime is 13414439977. The next prime is 13414440047. The reversal of 13414440000 is 4441431.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1555701 + ... + 1564299.

It is an arithmetic number, because the mean of its divisors is an integer number (170601640).

Almost surely, 213414440000 is an apocalyptic number.

13414440000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13414440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23884229600).

13414440000 is an abundant number, since it is smaller than the sum of its proper divisors (34354019200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13414440000 is an equidigital number, since it uses as much as digits as its factorization.

13414440000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8647 (or 8622 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 13414440000 its reverse (4441431), we get a palindrome (13418881431).

The spelling of 13414440000 in words is "thirteen billion, four hundred fourteen million, four hundred forty thousand".