Base | Representation |
---|---|
bin | 1100001100110100111111… |
… | …1100000100111000110100 |
3 | 1202111102020020120021002122 |
4 | 3003031033330010320310 |
5 | 3224240421121423012 |
6 | 44310314112455112 |
7 | 2553111260523053 |
oct | 303151774047064 |
9 | 52442206507078 |
10 | 13414524014132 |
11 | 43020820a995a |
12 | 16079a8b4a498 |
13 | 763ca4347c57 |
14 | 3453a310839a |
15 | 183e211c1e72 |
hex | c334ff04e34 |
13414524014132 has 12 divisors (see below), whose sum is σ = 23974893983040. Its totient is φ = 6564554304696.
The previous prime is 13414524014077. The next prime is 13414524014137. The reversal of 13414524014132 is 23141042541431.
13414524014132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13414524014092 and 13414524014101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13414524014137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35676925382 + ... + 35676925757.
It is an arithmetic number, because the mean of its divisors is an integer number (1997907831920).
Almost surely, 213414524014132 is an apocalyptic number.
It is an amenable number.
13414524014132 is a deficient number, since it is larger than the sum of its proper divisors (10560369968908).
13414524014132 is a wasteful number, since it uses less digits than its factorization.
13414524014132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71353851190 (or 71353851188 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 13414524014132 its reverse (23141042541431), we get a palindrome (36555566555563).
The spelling of 13414524014132 in words is "thirteen trillion, four hundred fourteen billion, five hundred twenty-four million, fourteen thousand, one hundred thirty-two".
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