Base | Representation |
---|---|
bin | 1100001100110110111011… |
… | …1001001000010101010001 |
3 | 1202111110120102202112002120 |
4 | 3003031232321020111101 |
5 | 3224243002043214010 |
6 | 44310441423404453 |
7 | 2553130164631410 |
oct | 303155671102521 |
9 | 52443512675076 |
10 | 13415043335505 |
11 | 4302319262779 |
12 | 1607b12a53729 |
13 | 764057b065c6 |
14 | 34541208d477 |
15 | 183e51aa4e70 |
hex | c336ee48551 |
13415043335505 has 64 divisors (see below), whose sum is σ = 26244739276800. Its totient is φ = 5714580222720.
The previous prime is 13415043335497. The next prime is 13415043335513. The reversal of 13415043335505 is 50553334051431.
It is an interprime number because it is at equal distance from previous prime (13415043335497) and next prime (13415043335513).
It is not a de Polignac number, because 13415043335505 - 23 = 13415043335497 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 54995785 + ... + 55239174.
It is an arithmetic number, because the mean of its divisors is an integer number (410074051200).
Almost surely, 213415043335505 is an apocalyptic number.
13415043335505 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13415043335505 is a deficient number, since it is larger than the sum of its proper divisors (12829695941295).
13415043335505 is a wasteful number, since it uses less digits than its factorization.
13415043335505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110235054.
The product of its (nonzero) digits is 810000, while the sum is 42.
Adding to 13415043335505 its reverse (50553334051431), we get a palindrome (63968377386936).
The spelling of 13415043335505 in words is "thirteen trillion, four hundred fifteen billion, forty-three million, three hundred thirty-five thousand, five hundred five".
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