Base | Representation |
---|---|
bin | 11000111111001110… |
… | …01000011111110001 |
3 | 1021121221011111212022 |
4 | 30133213020133301 |
5 | 204433301112001 |
6 | 10055103241225 |
7 | 653304530462 |
oct | 143747103761 |
9 | 37557144768 |
10 | 13415254001 |
11 | 5764619986 |
12 | 27248a9215 |
13 | 135a424426 |
14 | 913980d69 |
15 | 537b2a11b |
hex | 31f9c87f1 |
13415254001 has 2 divisors, whose sum is σ = 13415254002. Its totient is φ = 13415254000.
The previous prime is 13415253983. The next prime is 13415254003. The reversal of 13415254001 is 10045251431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13409871601 + 5382400 = 115801^2 + 2320^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13415254001 is a prime.
It is a super-2 number, since 2×134152540012 (a number of 21 digits) contains 22 as substring.
Together with 13415254003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13415254003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707627000 + 6707627001.
It is an arithmetic number, because the mean of its divisors is an integer number (6707627001).
Almost surely, 213415254001 is an apocalyptic number.
It is an amenable number.
13415254001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13415254001 is an equidigital number, since it uses as much as digits as its factorization.
13415254001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 26.
The spelling of 13415254001 in words is "thirteen billion, four hundred fifteen million, two hundred fifty-four thousand, one".
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