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13415305667 is a prime number
BaseRepresentation
bin11000111111001110…
…10101000111000011
31021121221021010201212
430133213111013003
5204433304240132
610055104320335
7653305134221
oct143747250703
937557233655
1013415305667
115764654785
1227249130ab
13135a441aba
14913995b11
15537b3a5b2
hex31f9d51c3

13415305667 has 2 divisors, whose sum is σ = 13415305668. Its totient is φ = 13415305666.

The previous prime is 13415305649. The next prime is 13415305669. The reversal of 13415305667 is 76650351431.

It is a strong prime.

It is an emirp because it is prime and its reverse (76650351431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13415305667 - 220 = 13414257091 is a prime.

It is a super-2 number, since 2×134153056672 (a number of 21 digits) contains 22 as substring.

Together with 13415305669, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13415305669) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707652833 + 6707652834.

It is an arithmetic number, because the mean of its divisors is an integer number (6707652834).

Almost surely, 213415305667 is an apocalyptic number.

13415305667 is a deficient number, since it is larger than the sum of its proper divisors (1).

13415305667 is an equidigital number, since it uses as much as digits as its factorization.

13415305667 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 41.

The spelling of 13415305667 in words is "thirteen billion, four hundred fifteen million, three hundred five thousand, six hundred sixty-seven".