Base | Representation |
---|---|
bin | 11000111111001111… |
… | …01011111011101011 |
3 | 1021121221102212222002 |
4 | 30133213223323223 |
5 | 204433320233042 |
6 | 10055110321215 |
7 | 653306003603 |
oct | 143747537353 |
9 | 37557385862 |
10 | 13415399147 |
11 | 5764708a37 |
12 | 272495920b |
13 | 135a475507 |
14 | 9139bbc03 |
15 | 537b58132 |
hex | 31f9ebeeb |
13415399147 has 2 divisors, whose sum is σ = 13415399148. Its totient is φ = 13415399146.
The previous prime is 13415399119. The next prime is 13415399149. The reversal of 13415399147 is 74199351431.
It is a strong prime.
It is an emirp because it is prime and its reverse (74199351431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13415399147 - 212 = 13415395051 is a prime.
Together with 13415399149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13415399149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707699573 + 6707699574.
It is an arithmetic number, because the mean of its divisors is an integer number (6707699574).
Almost surely, 213415399147 is an apocalyptic number.
13415399147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13415399147 is an equidigital number, since it uses as much as digits as its factorization.
13415399147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 408240, while the sum is 47.
The spelling of 13415399147 in words is "thirteen billion, four hundred fifteen million, three hundred ninety-nine thousand, one hundred forty-seven".
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