Base | Representation |
---|---|
bin | 11110100000001110111010… |
… | …001001000011011011000101 |
3 | 122121000020012000121202211021 |
4 | 132200032322021003123011 |
5 | 120041004330131113203 |
6 | 1153154340025111141 |
7 | 40154324211331063 |
oct | 3640167211033305 |
9 | 577006160552737 |
10 | 134156426426053 |
11 | 3982346a2a2a59 |
12 | 130684b79284b1 |
13 | 59b1b87160725 |
14 | 251b2c4581033 |
15 | 1079ab33ee5bd |
hex | 7a03ba2436c5 |
134156426426053 has 4 divisors (see below), whose sum is σ = 134156455312320. Its totient is φ = 134156397539788.
The previous prime is 134156426425949. The next prime is 134156426426129. The reversal of 134156426426053 is 350624624651431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 134156426426053 - 237 = 134018987472581 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134156426486053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5720893 + ... + 17350546.
It is an arithmetic number, because the mean of its divisors is an integer number (33539113828080).
Almost surely, 2134156426426053 is an apocalyptic number.
It is an amenable number.
134156426426053 is a deficient number, since it is larger than the sum of its proper divisors (28886267).
134156426426053 is an equidigital number, since it uses as much as digits as its factorization.
134156426426053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28886266.
The product of its (nonzero) digits is 12441600, while the sum is 52.
The spelling of 134156426426053 in words is "one hundred thirty-four trillion, one hundred fifty-six billion, four hundred twenty-six million, four hundred twenty-six thousand, fifty-three".
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