13417061326147 has 4 divisors (see below), whose sum is σ = 13417073178520. Its totient is φ = 13417049473776.

The previous prime is 13417061326139. The next prime is 13417061326169. The reversal of 13417061326147 is 74162316071431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13417061326147 - 2³ = 13417061326139 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13417061326097 and 13417061326106.

It is not an unprimeable number, because it can be changed into a prime (13417061326247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4024818 + ... + 6559975.

It is an arithmetic number, because the mean of its divisors is an integer number (3354268294630).

Almost surely, 2^{13417061326147} is an apocalyptic number.

13417061326147 is a deficient number, since it is larger than the sum of its proper divisors (11852373).

13417061326147 is a wasteful number, since it uses less digits than its factorization.

13417061326147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11852372.

The product of its (nonzero) digits is 508032, while the sum is 46.

Adding to 13417061326147 its reverse (74162316071431), we get a palindrome (87579377397578).

The spelling of 13417061326147 in words is "thirteen trillion, four hundred seventeen billion, sixty-one million, three hundred twenty-six thousand, one hundred forty-seven".