Base | Representation |
---|---|
bin | 11110100000011100001100… |
… | …001000110010010000100111 |
3 | 122121001120222212101110001022 |
4 | 132200130030020302100213 |
5 | 120041223031332124401 |
6 | 1153205055050321355 |
7 | 40155340462165265 |
oct | 3640341410622047 |
9 | 577046885343038 |
10 | 134170686989351 |
11 | 39829517a8a261 |
12 | 1306b21772925b |
13 | 59b331a74006c |
14 | 251bc784c3435 |
15 | 107a14a35171b |
hex | 7a070c232427 |
134170686989351 has 2 divisors, whose sum is σ = 134170686989352. Its totient is φ = 134170686989350.
The previous prime is 134170686989237. The next prime is 134170686989363. The reversal of 134170686989351 is 153989686071431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134170686989351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134170686989371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67085343494675 + 67085343494676.
It is an arithmetic number, because the mean of its divisors is an integer number (67085343494676).
Almost surely, 2134170686989351 is an apocalyptic number.
134170686989351 is a deficient number, since it is larger than the sum of its proper divisors (1).
134170686989351 is an equidigital number, since it uses as much as digits as its factorization.
134170686989351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 235146240, while the sum is 71.
The spelling of 134170686989351 in words is "one hundred thirty-four trillion, one hundred seventy billion, six hundred eighty-six million, nine hundred eighty-nine thousand, three hundred fifty-one".
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