Base | Representation |
---|---|
bin | 11000111111100010… |
… | …11101001111111001 |
3 | 1021122010021000101211 |
4 | 30133301131033321 |
5 | 204434444213231 |
6 | 10055241243121 |
7 | 653336532124 |
oct | 143761351771 |
9 | 37563230354 |
10 | 13417960441 |
11 | 57660a8306 |
12 | 27257934a1 |
13 | 135ab61282 |
14 | 9140873bb |
15 | 537eb1eb1 |
hex | 31fc5d3f9 |
13417960441 has 2 divisors, whose sum is σ = 13417960442. Its totient is φ = 13417960440.
The previous prime is 13417960373. The next prime is 13417960453. The reversal of 13417960441 is 14406971431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8548851600 + 4869108841 = 92460^2 + 69779^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13417960441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13417960394 and 13417960403.
It is not a weakly prime, because it can be changed into another prime (13417960541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6708980220 + 6708980221.
It is an arithmetic number, because the mean of its divisors is an integer number (6708980221).
Almost surely, 213417960441 is an apocalyptic number.
It is an amenable number.
13417960441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13417960441 is an equidigital number, since it uses as much as digits as its factorization.
13417960441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 40.
The spelling of 13417960441 in words is "thirteen billion, four hundred seventeen million, nine hundred sixty thousand, four hundred forty-one".
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