Base | Representation |
---|---|
bin | 1100001101000010011110… |
… | …1011011000101011111010 |
3 | 1202111202120111022002012111 |
4 | 3003100213223120223322 |
5 | 3224320324220024214 |
6 | 44312113211202534 |
7 | 2553300051014605 |
oct | 303204753305372 |
9 | 52452514262174 |
10 | 13418143517434 |
11 | 430366a2292a7 |
12 | 160863914644a |
13 | 764430196396 |
14 | 345627ad333c |
15 | 184083d375c4 |
hex | c3427ad8afa |
13418143517434 has 4 divisors (see below), whose sum is σ = 20127215276154. Its totient is φ = 6709071758716.
The previous prime is 13418143517423. The next prime is 13418143517437. The reversal of 13418143517434 is 43471534181431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9470359986025 + 3947783531409 = 3077395^2 + 1986903^2 .
It is not an unprimeable number, because it can be changed into a prime (13418143517437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3354535879357 + ... + 3354535879360.
Almost surely, 213418143517434 is an apocalyptic number.
13418143517434 is a deficient number, since it is larger than the sum of its proper divisors (6709071758720).
13418143517434 is an equidigital number, since it uses as much as digits as its factorization.
13418143517434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6709071758719.
The product of its digits is 1935360, while the sum is 49.
Adding to 13418143517434 its reverse (43471534181431), we get a palindrome (56889677698865).
The spelling of 13418143517434 in words is "thirteen trillion, four hundred eighteen billion, one hundred forty-three million, five hundred seventeen thousand, four hundred thirty-four".
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