134190749385216 has 1440 divisors, whose sum is σ = 444249686200320. Its totient is φ = 40386030796800.

The previous prime is 134190749385211. The next prime is 134190749385223. The reversal of 134190749385216 is 612583947091431.

134190749385216 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 9 + 0 + 74 + 9 + 38 + 521 + 6 = 666.

It is not an unprimeable number, because it can be changed into a prime (134190749385211) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 146018225205 + ... + 146018226123.

It is an arithmetic number, because the mean of its divisors is an integer number (308506726528).

It is a 1-persistent number, because it is pandigital, but 2⋅134190749385216 = 268381498770432 is not.

Almost surely, 2^{134190749385216} is an apocalyptic number.

134190749385216 is a gapful number since it is divisible by the number (16) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134190749385216, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222124843100160).

134190749385216 is an abundant number, since it is smaller than the sum of its proper divisors (310058936815104).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134190749385216 is an equidigital number, since it uses as much as digits as its factorization.

134190749385216 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1148 (or 1103 counting only the distinct ones).

The product of its (nonzero) digits is 39191040, while the sum is 63.

The spelling of 134190749385216 in words is "one hundred thirty-four trillion, one hundred ninety billion, seven hundred forty-nine million, three hundred eighty-five thousand, two hundred sixteen".