Base | Representation |
---|---|
bin | 11110100000110111100001… |
… | …001100100001100100010111 |
3 | 122121011101201220220220122002 |
4 | 132200313201030201210113 |
5 | 120042213131004222333 |
6 | 1153230350541225515 |
7 | 40160426610656552 |
oct | 3640674114414427 |
9 | 577141656826562 |
10 | 134200031320343 |
11 | 3983aa0610247a |
12 | 13074a46b6229b |
13 | 59b6016017a21 |
14 | 251d45d813699 |
15 | 107acb66130e8 |
hex | 7a0de1321917 |
134200031320343 has 4 divisors (see below), whose sum is σ = 134201495854320. Its totient is φ = 134198566786368.
The previous prime is 134200031320331. The next prime is 134200031320391. The reversal of 134200031320343 is 343023130002431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134200031320343 - 26 = 134200031320279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134200031380343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 732129530 + ... + 732312807.
It is an arithmetic number, because the mean of its divisors is an integer number (33550373963580).
Almost surely, 2134200031320343 is an apocalyptic number.
134200031320343 is a deficient number, since it is larger than the sum of its proper divisors (1464533977).
134200031320343 is an equidigital number, since it uses as much as digits as its factorization.
134200031320343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1464533976.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 134200031320343 its reverse (343023130002431), we get a palindrome (477223161322774).
The spelling of 134200031320343 in words is "one hundred thirty-four trillion, two hundred billion, thirty-one million, three hundred twenty thousand, three hundred forty-three".
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