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134201129983 is a prime number
BaseRepresentation
bin111110011111100000…
…0101011101111111111
3110211101201002202112121
41330333000223233333
54144320442124413
6141352351543411
712460425532504
oct1747700535777
9424351082477
10134201129983
1151a07048288
122201382ab67
13c86938796b
1466d14174ab
153756ab7b8d
hex1f3f02bbff

134201129983 has 2 divisors, whose sum is σ = 134201129984. Its totient is φ = 134201129982.

The previous prime is 134201129963. The next prime is 134201130001. The reversal of 134201129983 is 389921102431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134201129983 - 29 = 134201129471 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134201129963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67100564991 + 67100564992.

It is an arithmetic number, because the mean of its divisors is an integer number (67100564992).

Almost surely, 2134201129983 is an apocalyptic number.

134201129983 is a deficient number, since it is larger than the sum of its proper divisors (1).

134201129983 is an equidigital number, since it uses as much as digits as its factorization.

134201129983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 43.

The spelling of 134201129983 in words is "one hundred thirty-four billion, two hundred one million, one hundred twenty-nine thousand, nine hundred eighty-three".