Base | Representation |
---|---|
bin | 1100001101001001111001… |
… | …0101110010001011111111 |
3 | 1202111221201020101112001101 |
4 | 3003102132111302023333 |
5 | 3224333413342442143 |
6 | 44313042525353531 |
7 | 2553400303530163 |
oct | 303223625621377 |
9 | 52457636345041 |
10 | 13420134343423 |
11 | 43044a0a7a335 |
12 | 1608ab3a088a7 |
13 | 76468977ab22 |
14 | 345776280ca3 |
15 | 18414d9d6b4d |
hex | c349e5722ff |
13420134343423 has 4 divisors (see below), whose sum is σ = 13550426909968. Its totient is φ = 13289841776880.
The previous prime is 13420134343393. The next prime is 13420134343487. The reversal of 13420134343423 is 32434343102431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13420134343423 - 25 = 13420134343391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13420134343123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65146283118 + ... + 65146283323.
It is an arithmetic number, because the mean of its divisors is an integer number (3387606727492).
Almost surely, 213420134343423 is an apocalyptic number.
13420134343423 is a deficient number, since it is larger than the sum of its proper divisors (130292566545).
13420134343423 is a wasteful number, since it uses less digits than its factorization.
13420134343423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 130292566544.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 13420134343423 its reverse (32434343102431), we get a palindrome (45854477445854).
The spelling of 13420134343423 in words is "thirteen trillion, four hundred twenty billion, one hundred thirty-four million, three hundred forty-three thousand, four hundred twenty-three".
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