Base | Representation |
---|---|
bin | 10011100001110110010… |
… | …010000100010101101011 |
3 | 11202021222021120012022210 |
4 | 103201312102010111223 |
5 | 133441421121303303 |
6 | 2504302434420203 |
7 | 165646235601303 |
oct | 23416622042553 |
9 | 4667867505283 |
10 | 1342014244203 |
11 | 478166066766 |
12 | 198111a31663 |
13 | 99722570679 |
14 | 48d4d47c603 |
15 | 24d97685203 |
hex | 1387648456b |
1342014244203 has 8 divisors (see below), whose sum is σ = 1789541973648. Its totient is φ = 894581338784.
The previous prime is 1342014244187. The next prime is 1342014244229. The reversal of 1342014244203 is 3024424102431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1342014244203 - 24 = 1342014244187 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1342014244253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23672976 + ... + 23729597.
It is an arithmetic number, because the mean of its divisors is an integer number (223692746706).
Almost surely, 21342014244203 is an apocalyptic number.
1342014244203 is a deficient number, since it is larger than the sum of its proper divisors (447527729445).
1342014244203 is an equidigital number, since it uses as much as digits as its factorization.
1342014244203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47412013.
The product of its (nonzero) digits is 18432, while the sum is 30.
Adding to 1342014244203 its reverse (3024424102431), we get a palindrome (4366438346634).
The spelling of 1342014244203 in words is "one trillion, three hundred forty-two billion, fourteen million, two hundred forty-four thousand, two hundred three".
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