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13420325544481 is a prime number
BaseRepresentation
bin1100001101001010100110…
…1111001010001000100001
31202111222012120011112121001
43003102221233022020201
53224334311314410411
644313113515432001
72553405114646522
oct303225157121041
952458176145531
1013420325544481
1143045899a2539
121608b47a55601
137646ba27414b
14345793812849
151841606a3dc1
hexc34a9bca221

13420325544481 has 2 divisors, whose sum is σ = 13420325544482. Its totient is φ = 13420325544480.

The previous prime is 13420325544421. The next prime is 13420325544523. The reversal of 13420325544481 is 18444552302431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12710829300625 + 709496243856 = 3565225^2 + 842316^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13420325544481 is a prime.

It is a super-2 number, since 2×134203255444812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13420325544421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710162772240 + 6710162772241.

It is an arithmetic number, because the mean of its divisors is an integer number (6710162772241).

Almost surely, 213420325544481 is an apocalyptic number.

It is an amenable number.

13420325544481 is a deficient number, since it is larger than the sum of its proper divisors (1).

13420325544481 is an equidigital number, since it uses as much as digits as its factorization.

13420325544481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1843200, while the sum is 46.

The spelling of 13420325544481 in words is "thirteen trillion, four hundred twenty billion, three hundred twenty-five million, five hundred forty-four thousand, four hundred eighty-one".