13420325544421 has 2 divisors, whose sum is σ = 13420325544422. Its totient is φ = 13420325544420.

The previous prime is 13420325544359. The next prime is 13420325544481. The reversal of 13420325544421 is 12444552302431.

13420325544421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7209708308100 + 6210617236321 = 2685090^2 + 2492111^2 .

It is an emirp because it is prime and its reverse (12444552302431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13420325544421 - 2¹¹ = 13420325542373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13420325544481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710162772210 + 6710162772211.

It is an arithmetic number, because the mean of its divisors is an integer number (6710162772211).

Almost surely, 2^{13420325544421} is an apocalyptic number.

It is an amenable number.

13420325544421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13420325544421 is an equidigital number, since it uses as much as digits as its factorization.

13420325544421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 13420325544421 its reverse (12444552302431), we get a palindrome (25864877846852).

The spelling of 13420325544421 in words is "thirteen trillion, four hundred twenty billion, three hundred twenty-five million, five hundred forty-four thousand, four hundred twenty-one".