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13420341041 = 19706333739
BaseRepresentation
bin11000111111110101…
…00010011100110001
31021122021201221222012
430133322202130301
5204441101403131
610055404252305
7653366005502
oct143772423461
937567657865
1013420341041
115767483948
122726541095
13135b4b5a03
14914506ba9
155382d252b
hex31fea2731

13420341041 has 4 divisors (see below), whose sum is σ = 14126674800. Its totient is φ = 12714007284.

The previous prime is 13420341017. The next prime is 13420341043. The reversal of 13420341041 is 14014302431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13420341041 - 230 = 12346599217 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13420340998 and 13420341016.

It is not an unprimeable number, because it can be changed into a prime (13420341043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353166851 + ... + 353166888.

It is an arithmetic number, because the mean of its divisors is an integer number (3531668700).

Almost surely, 213420341041 is an apocalyptic number.

It is an amenable number.

13420341041 is a deficient number, since it is larger than the sum of its proper divisors (706333759).

13420341041 is an equidigital number, since it uses as much as digits as its factorization.

13420341041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 706333758.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13420341041 its reverse (14014302431), we get a palindrome (27434643472).

The spelling of 13420341041 in words is "thirteen billion, four hundred twenty million, three hundred forty-one thousand, forty-one".

Divisors: 1 19 706333739 13420341041