Base | Representation |
---|---|
bin | 111110011111101010… |
… | …0100011101100111111 |
3 | 110211102001220110012121 |
4 | 1330333110203230333 |
5 | 4144323310334103 |
6 | 141353055343411 |
7 | 12460521031666 |
oct | 1747724435477 |
9 | 424361813177 |
10 | 134206339903 |
11 | 51a09a865a9 |
12 | 22015521b67 |
13 | c86a49015c |
14 | 66d1db1ddd |
15 | 37572966bd |
hex | 1f3f523b3f |
134206339903 has 4 divisors (see below), whose sum is σ = 134251728840. Its totient is φ = 134160950968.
The previous prime is 134206339831. The next prime is 134206339907. The reversal of 134206339903 is 309933602431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134206339903 - 213 = 134206331711 is a prime.
It is a super-2 number, since 2×1342063399032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 134206339903.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134206339907) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22690033 + ... + 22695946.
It is an arithmetic number, because the mean of its divisors is an integer number (33562932210).
Almost surely, 2134206339903 is an apocalyptic number.
134206339903 is a deficient number, since it is larger than the sum of its proper divisors (45388937).
134206339903 is an equidigital number, since it uses as much as digits as its factorization.
134206339903 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45388936.
The product of its (nonzero) digits is 314928, while the sum is 43.
The spelling of 134206339903 in words is "one hundred thirty-four billion, two hundred six million, three hundred thirty-nine thousand, nine hundred three".
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