Base | Representation |
---|---|
bin | 11000111111110111… |
… | …01100111111010001 |
3 | 1021122022022110210001 |
4 | 30133323230333101 |
5 | 204441141140403 |
6 | 10055415010001 |
7 | 653401416562 |
oct | 143773547721 |
9 | 37568273701 |
10 | 13420646353 |
11 | 5767672274 |
12 | 2726669901 |
13 | 135b59197a |
14 | 914586169 |
15 | 538342c1d |
hex | 31feecfd1 |
13420646353 has 2 divisors, whose sum is σ = 13420646354. Its totient is φ = 13420646352.
The previous prime is 13420646347. The next prime is 13420646357. The reversal of 13420646353 is 35364602431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11687339664 + 1733306689 = 108108^2 + 41633^2 .
It is an emirp because it is prime and its reverse (35364602431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13420646353 - 221 = 13418549201 is a prime.
It is a super-2 number, since 2×134206463532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13420646357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710323176 + 6710323177.
It is an arithmetic number, because the mean of its divisors is an integer number (6710323177).
Almost surely, 213420646353 is an apocalyptic number.
It is an amenable number.
13420646353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13420646353 is an equidigital number, since it uses as much as digits as its factorization.
13420646353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 37.
The spelling of 13420646353 in words is "thirteen billion, four hundred twenty million, six hundred forty-six thousand, three hundred fifty-three".
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