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13421113200001 = 131032393323077
BaseRepresentation
bin1100001101001101100010…
…1011110100110110000001
31202112001020110021120211201
43003103120223310312001
53224342414434400001
644313324013541201
72553433460630353
oct303233053646601
952461213246751
1013421113200001
114304953571811
1216091277a4801
137647b44c42c0
1434582a2870d3
151841a98dd501
hexc34d8af4d81

13421113200001 has 4 divisors (see below), whose sum is σ = 14453506523092. Its totient is φ = 12388719876912.

The previous prime is 13421113199983. The next prime is 13421113200017. The reversal of 13421113200001 is 10000231112431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2429932262976 + 10991180937025 = 1558824^2 + 3315295^2 .

It is a cyclic number.

It is not a de Polignac number, because 13421113200001 - 29 = 13421113199489 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13421113204001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 516196661526 + ... + 516196661551.

It is an arithmetic number, because the mean of its divisors is an integer number (3613376630773).

Almost surely, 213421113200001 is an apocalyptic number.

It is an amenable number.

13421113200001 is a deficient number, since it is larger than the sum of its proper divisors (1032393323091).

13421113200001 is a wasteful number, since it uses less digits than its factorization.

13421113200001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1032393323090.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13421113200001 its reverse (10000231112431), we get a palindrome (23421344312432).

The spelling of 13421113200001 in words is "thirteen trillion, four hundred twenty-one billion, one hundred thirteen million, two hundred thousand, one".

Divisors: 1 13 1032393323077 13421113200001