13421202312421 has 4 divisors (see below), whose sum is σ = 13783937510092. Its totient is φ = 13058467114752.

The previous prime is 13421202312409. The next prime is 13421202312433. The reversal of 13421202312421 is 12421320212431.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13421202312409) and next prime (13421202312433).

It can be written as a sum of positive squares in 2 ways, for example, as 7364873268900 + 6056329043521 = 2713830^2 + 2460961^2 .

It is a cyclic number.

It is not a de Polignac number, because 13421202312421 - 2¹⁷ = 13421202181349 is a prime.

It is a super-3 number, since 3×13421202312421³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13421202312421.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13421202352421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181367598780 + ... + 181367598853.

It is an arithmetic number, because the mean of its divisors is an integer number (3445984377523).

Almost surely, 2^{13421202312421} is an apocalyptic number.

It is an amenable number.

13421202312421 is a deficient number, since it is larger than the sum of its proper divisors (362735197671).

13421202312421 is an equidigital number, since it uses as much as digits as its factorization.

13421202312421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 362735197670.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 13421202312421 its reverse (12421320212431), we get a palindrome (25842522524852).

The spelling of 13421202312421 in words is "thirteen trillion, four hundred twenty-one billion, two hundred two million, three hundred twelve thousand, four hundred twenty-one".