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134214044101 = 1116231202387
BaseRepresentation
bin111110011111111000…
…1111100100111000101
3110211102121101212101021
41330333301330213011
54144332243402401
6141353532431141
712460643360134
oct1747761744705
9424377355337
10134214044101
1151a13368905
12220180184b1
13c86bc59a57
1466d301991b
153757cb92a1
hex1f3fc7c9c5

134214044101 has 4 divisors (see below), whose sum is σ = 134215358112. Its totient is φ = 134212730092.

The previous prime is 134214044099. The next prime is 134214044131. The reversal of 134214044101 is 101440412431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134214044101 - 21 = 134214044099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134214044131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 489571 + ... + 712816.

It is an arithmetic number, because the mean of its divisors is an integer number (33553839528).

Almost surely, 2134214044101 is an apocalyptic number.

It is an amenable number.

134214044101 is a deficient number, since it is larger than the sum of its proper divisors (1314011).

134214044101 is a wasteful number, since it uses less digits than its factorization.

134214044101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1314010.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 134214044101 its reverse (101440412431), we get a palindrome (235654456532).

The spelling of 134214044101 in words is "one hundred thirty-four billion, two hundred fourteen million, forty-four thousand, one hundred one".

Divisors: 1 111623 1202387 134214044101