Base | Representation |
---|---|
bin | 10011100001111110011… |
… | …100101001011010001011 |
3 | 11202022022211100001122211 |
4 | 103201332130221122023 |
5 | 133442211204011321 |
6 | 2504324210525551 |
7 | 165652521160063 |
oct | 23417634513213 |
9 | 4668284301584 |
10 | 1342151235211 |
11 | 478226423076 |
12 | 19814b8968b7 |
13 | 99744a66237 |
14 | 48d6373c3a3 |
15 | 24da46e50e1 |
hex | 1387e72968b |
1342151235211 has 2 divisors, whose sum is σ = 1342151235212. Its totient is φ = 1342151235210.
The previous prime is 1342151235199. The next prime is 1342151235223. The reversal of 1342151235211 is 1125321512431.
It is a balanced prime because it is at equal distance from previous prime (1342151235199) and next prime (1342151235223).
It is a cyclic number.
It is not a de Polignac number, because 1342151235211 - 217 = 1342151104139 is a prime.
It is not a weakly prime, because it can be changed into another prime (1342151235311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671075617605 + 671075617606.
It is an arithmetic number, because the mean of its divisors is an integer number (671075617606).
Almost surely, 21342151235211 is an apocalyptic number.
1342151235211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342151235211 is an equidigital number, since it uses as much as digits as its factorization.
1342151235211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7200, while the sum is 31.
Adding to 1342151235211 its reverse (1125321512431), we get a palindrome (2467472747642).
The spelling of 1342151235211 in words is "one trillion, three hundred forty-two billion, one hundred fifty-one million, two hundred thirty-five thousand, two hundred eleven".
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