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134215222313819 is a prime number
BaseRepresentation
bin11110100001000101101010…
…101001100100001101011011
3122121012211221121110100010002
4132201011222221210031123
5120042440233403020234
61153241342201043215
740161505220202353
oct3641055251441533
9577184847410102
10134215222313819
11398463a1015739
121307798648650b
1359b75972b676a
1425200a1153b63
15107b3a50a327e
hex7a116aa6435b

134215222313819 has 2 divisors, whose sum is σ = 134215222313820. Its totient is φ = 134215222313818.

The previous prime is 134215222313789. The next prime is 134215222313827. The reversal of 134215222313819 is 918313222512431.

It is a strong prime.

It is an emirp because it is prime and its reverse (918313222512431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134215222313819 - 244 = 116623036269403 is a prime.

It is a super-2 number, since 2×1342152223138192 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134215222313839) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67107611156909 + 67107611156910.

It is an arithmetic number, because the mean of its divisors is an integer number (67107611156910).

Almost surely, 2134215222313819 is an apocalyptic number.

134215222313819 is a deficient number, since it is larger than the sum of its proper divisors (1).

134215222313819 is an equidigital number, since it uses as much as digits as its factorization.

134215222313819 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 622080, while the sum is 47.

The spelling of 134215222313819 in words is "one hundred thirty-four trillion, two hundred fifteen billion, two hundred twenty-two million, three hundred thirteen thousand, eight hundred nineteen".