Base | Representation |
---|---|
bin | 11000111111111110… |
… | …01010010101110011 |
3 | 1021122101000112110222 |
4 | 30133333022111303 |
5 | 204441404144021 |
6 | 10055450243255 |
7 | 653412214106 |
oct | 143777122563 |
9 | 37571015428 |
10 | 13421553011 |
11 | 5768131479 |
12 | 2726a2652b |
13 | 135b81b559 |
14 | 91474073d |
15 | 5384716ab |
hex | 31ffca573 |
13421553011 has 2 divisors, whose sum is σ = 13421553012. Its totient is φ = 13421553010.
The previous prime is 13421552987. The next prime is 13421553037. The reversal of 13421553011 is 11035512431.
It is an a-pointer prime, because the next prime (13421553037) can be obtained adding 13421553011 to its sum of digits (26).
It is a weak prime.
It is an emirp because it is prime and its reverse (11035512431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13421553011 - 214 = 13421536627 is a prime.
It is a super-2 number, since 2×134215530112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13421553511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710776505 + 6710776506.
It is an arithmetic number, because the mean of its divisors is an integer number (6710776506).
Almost surely, 213421553011 is an apocalyptic number.
13421553011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13421553011 is an equidigital number, since it uses as much as digits as its factorization.
13421553011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 26.
The spelling of 13421553011 in words is "thirteen billion, four hundred twenty-one million, five hundred fifty-three thousand, eleven".
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