Search a number
-
+
13421949243613 = 64492081245037
BaseRepresentation
bin1100001101010000101010…
…0001000101000011011101
31202112010101201110000001221
43003110022201011003131
53224401123001243423
644313543001133341
72553463262113321
oct303241241050335
952463351400057
1013421949243613
114305242490749
12160931b78a251
137648b8786c71
143458a9315981
15184207ed4e5d
hexc350a8450dd

13421949243613 has 4 divisors (see below), whose sum is σ = 13424030495100. Its totient is φ = 13419867992128.

The previous prime is 13421949243611. The next prime is 13421949243701. The reversal of 13421949243613 is 31634294912431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12018300094564 + 1403649149049 = 3466742^2 + 1184757^2 .

It is a cyclic number.

It is not a de Polignac number, because 13421949243613 - 21 = 13421949243611 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13421949243611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1040616070 + ... + 1040628967.

It is an arithmetic number, because the mean of its divisors is an integer number (3356007623775).

Almost surely, 213421949243613 is an apocalyptic number.

It is an amenable number.

13421949243613 is a deficient number, since it is larger than the sum of its proper divisors (2081251487).

13421949243613 is an equidigital number, since it uses as much as digits as its factorization.

13421949243613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2081251486.

The product of its digits is 3359232, while the sum is 52.

The spelling of 13421949243613 in words is "thirteen trillion, four hundred twenty-one billion, nine hundred forty-nine million, two hundred forty-three thousand, six hundred thirteen".

Divisors: 1 6449 2081245037 13421949243613