Base | Representation |
---|---|
bin | 1100001101010001101101… |
… | …0101011111110011010001 |
3 | 1202112011010101102001110102 |
4 | 3003110123111133303101 |
5 | 3224402212220420423 |
6 | 44314031001142145 |
7 | 2553503256430325 |
oct | 303243325376321 |
9 | 52464111361412 |
10 | 13422231420113 |
11 | 43053777a106a |
12 | 160939a18a955 |
13 | 7649320841c9 |
14 | 3458d49a9985 |
15 | 184222b72c28 |
hex | c351b55fcd1 |
13422231420113 has 2 divisors, whose sum is σ = 13422231420114. Its totient is φ = 13422231420112.
The previous prime is 13422231420109. The next prime is 13422231420137. The reversal of 13422231420113 is 31102413222431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9196711281664 + 4225520138449 = 3032608^2 + 2055607^2 .
It is a cyclic number.
It is not a de Polignac number, because 13422231420113 - 22 = 13422231420109 is a prime.
It is not a weakly prime, because it can be changed into another prime (13422231426113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711115710056 + 6711115710057.
It is an arithmetic number, because the mean of its divisors is an integer number (6711115710057).
Almost surely, 213422231420113 is an apocalyptic number.
It is an amenable number.
13422231420113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13422231420113 is an equidigital number, since it uses as much as digits as its factorization.
13422231420113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13422231420113 its reverse (31102413222431), we get a palindrome (44524644642544).
The spelling of 13422231420113 in words is "thirteen trillion, four hundred twenty-two billion, two hundred thirty-one million, four hundred twenty thousand, one hundred thirteen".
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